輸入month=18，結果不對

答案有個問題，就是month>12的時候，程序不是輸出“一年只有12個月哦”后就終止，而是繼續往下執行，最后輸出“一年只有12個月哦2008年18月8日是該年的第9天”，如何處理可以在month>12時輸出一年只有12個月哦，然后終止呢？求教

書笑

2015-12-30

源自：C語言入門 4-17

關注問題我要回答

890

操作

收起

6 回答

1100001 回答被采納 +3 積分
2015-12-30

慘痛的教訓啊，需要寫代碼的回答我再也不會這么草率了，寫完一定要仔細檢查。

題主，代碼我重寫了，這次一定沒問題，嗯！

#include?"stdio.h"
main()
{
?int?year,month,day,iday=0,mday;
?printf("請輸入年/月/日：\n");
?scanf("%d/%d/%d",&year,&month,&day);
?switch(month)
?{
????????case?1:iday=0;mday=31;break;
????????case?2:iday=31;mday=28;break;
????????case?3:iday=59;mday=31;break;
????????case?4:iday=90;mday=30;break;
????????case?5:iday=120;mday=31;break;
????????case?6:iday=151;mday=30;break;
????????case?7:iday=181;mday=31;break;
????????case?8:iday=212;mday=31;break;
????????case?9:iday=243;mday=30;break;
????????case?10:iday=273;mday=31;break;
????????case?11:iday=304;mday=30;break;
????????case?12:iday=334;mday=31;break;
?}
?if((year%400==0)||(year%100!=0&&year%4==0)&&month==2)?mday++;
?if(month<=12&&month>=1)
?{
??iday+=day;
??if((year%400==0)||(year%100!=0&&year%4==0)&&month>2)?iday++;
??if(day>0&&day<=mday)
???printf("%d年%d月%d日是該年的第%d天",year,month,day,iday);
??else
???printf("%d月沒有%d日哦",month,day);
?}
?else
??printf("一年中只有12個月哦");
}

0 回復有任何疑惑可以回復我~

收起回答

書笑提問者

非常感謝！

2016-01-01 回復有任何疑惑可以回復我~

1100001
2015-12-30

goto只是一個玩笑罷了，雖然也能做，但是肯定會被批判一番；

題主想要的是可以輸出某月某日是一年當中的第幾天的程序，并且能對錯誤輸入有相應的反饋，那么我的答案如下；

#include?"stdio.h"
int?imonth(int?year,int?month);
main()
{
?int?year,month,day,iday=0,mday;
?printf("請輸入年/月/日\n");
?scanf("%d/%d/%d",&year,&month,&day);
?switch(month)
?{
??case?12:iday+=31;
??case?11:iday+=30;
??case?10:iday+=31;
??case?9:iday+=30;
??case?8:iday+=31;
??case?7:iday+=31;
??case?6:iday+=30;
??case?5:iday+=31;
??case?4:iday+=30;
??case?3:iday+=31;
??case?2:iday+=28;
??case?1:iday+=31;
?}
?mday=imonth(year,month);
?if((year%400==0)||(year%100!=0&&year%4==0))?iday++;
?if(month<=12&&month>=1)
?{
??iday+=day;
??if(day>0&&day<=mday)
???printf("%d年%d月%d日是該年的第%d天",year,month,day,iday);
??else
???printf("%d月沒有%d日哦",month,day);
?}
?else
??printf("一年中只有12個月哦");
}
int?imonth(int?year,int?month)
{
?int?iday=0;
?switch(month)
?{
??case?12:iday+=31;break;
??case?11:iday+=30;break;
??case?10:iday+=31;break;
??case?9:iday+=30;break;
??case?8:iday+=31;break;
??case?7:iday+=31;break;
??case?6:iday+=30;break;
??case?5:iday+=31;break;
??case?4:iday+=30;break;
??case?3:iday+=31;break;
??case?2:iday+=28;break;
??case?1:iday+=31;break;
?}
?if((year%400==0)||(year%100!=0&&year%4==0))?iday++;
?return?iday;
}

有對月份的檢查，也有對日期的檢查。

0 回復有任何疑惑可以回復我~

收起回答

1100001

丟死人了，題主請不要采納，我寫錯了

2015-12-30 回復有任何疑惑可以回復我~