已采納回答 / hdadan
precedencegroup ComparativePrecedence{ ? ? ? ? //定義運算符優先級? ? associativity: right? ? higherThan: LogicalConjunctionPrecedence}infix operator ** : ComparativePrecedencefunc **(x: Double, p:Double) -> Double{?? ?? ? return pow(x,p)}
2017-03-11