double money = 60000.00;//存款金額
if(money>50000)
{
Console.WriteLine("送一套茶具");
}
else
{
Console.WriteLine("沒有禮品");
}
最簡單的答案,也能通過
if(money>50000)
{
Console.WriteLine("送一套茶具");
}
else
{
Console.WriteLine("沒有禮品");
}
最簡單的答案,也能通過
string[,] arr = new string[,]{{"吳松","89"},{"錢東宇","90"},{"伏晨","98"},{"陳陸","56"},{"周蕊","60"},{"林日鵬","91"},{"何昆","93"},{"關欣","85"}};
int m = 0;int s;string n=null;
for(int i=0;i<arr.GetLongLength(0);i++)
{s = int.Parse(arr[i,1]);if(m<s){m = s;n = arr[i,0];}}
Console.Write("分數最高的是{0},分數是{1}",n,m);
int m = 0;int s;string n=null;
for(int i=0;i<arr.GetLongLength(0);i++)
{s = int.Parse(arr[i,1]);if(m<s){m = s;n = arr[i,0];}}
Console.Write("分數最高的是{0},分數是{1}",n,m);
Q1:這段程序計算變量d和x的和,并打印。但是d和x的類型不同,計算會出錯嗎?
A1:會出錯,左右精度不同
Q2:那么,程序運行的結果會是多少呢?
A2: 結果為3,2.5的精度到一位小數,(int)2.5相當于將小數部分去掉,所以2+1=3
A1:會出錯,左右精度不同
Q2:那么,程序運行的結果會是多少呢?
A2: 結果為3,2.5的精度到一位小數,(int)2.5相當于將小數部分去掉,所以2+1=3
2017-10-26
string[] names = new string[]{"吳松","錢東宇","伏晨","陳陸","周蕊","林日鵬","何昆","關欣"};
int[] scores = {89,90,98,56,60,91,93,85};
int max = 0;
string name = "";
for(int i=0;i<scores.Length;i++){
if(scores[i]>max){
max = scores[i];
name = names[i];
}
}
Console.Write("分數最高的是{0},分數是{1}",name, max);
int[] scores = {89,90,98,56,60,91,93,85};
int max = 0;
string name = "";
for(int i=0;i<scores.Length;i++){
if(scores[i]>max){
max = scores[i];
name = names[i];
}
}
Console.Write("分數最高的是{0},分數是{1}",name, max);