#include <stdio.h>
int main()
{
int arrFirst[3] = {4,5,6};
int arrSecond[] = {7,2,9};
int arrThird[3];
arrThird[0]=10;
arrThird[1]=0;
arrThird[2]=12;
printf("%d\n", arrFirst[1]);
printf("%d\n",arrSecond[1]);
printf("%d\n", arrThird[1]);
return 0;
}
輸出結果：520
int main()
{
int arrFirst[3] = {4,5,6};
int arrSecond[] = {7,2,9};
int arrThird[3];
arrThird[0]=10;
arrThird[1]=0;
arrThird[2]=12;
printf("%d\n", arrFirst[1]);
printf("%d\n",arrSecond[1]);
printf("%d\n", arrThird[1]);
return 0;
}
輸出結果：520
#include <stdio.h>
int main()
{
int arrFirst[3] = {4,5,6};
int arrSecond[] = {7,2,9};
int arrThird[3];
arrThird[0]=10;
arrThird[1]=0;
arrThird[2]=12;
printf("%d\n", arrFirst[1]);
printf("%d\n",arrSecond[1]);
printf("%d\n", arrThird[1]);
return 0;
}
int main()
{
int arrFirst[3] = {4,5,6};
int arrSecond[] = {7,2,9};
int arrThird[3];
arrThird[0]=10;
arrThird[1]=0;
arrThird[2]=12;
printf("%d\n", arrFirst[1]);
printf("%d\n",arrSecond[1]);
printf("%d\n", arrThird[1]);
return 0;
}
#include <stdio.h>
int main()
{
int i, j, k;
for(i=1; i<5; i++)
{
for(j=3;j>=i;j--)
{
printf(" ");
}
for(k=1;k<2*i;k++)
{
printf("*");
}
printf("\n");
}
return 0;
}
int main()
{
int i, j, k;
for(i=1; i<5; i++)
{
for(j=3;j>=i;j--)
{
printf(" ");
}
for(k=1;k<2*i;k++)
{
printf("*");
}
printf("\n");
}
return 0;
}
2023-04-03
最贊回答 / 大哥布
//這是另一種解法：#include <stdio.h>float Price(int km,int H)? ? ?//定義表示總價的函數，影響總價的變量有距離Km、上下班時間H1、H2。{? ? float cost;? ? ?//定義總價變量，用來承載每次計算的結果。? ? if(km>3)? ? {? ? ? ? if(H>=23||H<5)? ? ?//上、下班時間在晚間高收費區。? ? ? ? {? ? ? ? ? ? cost=(km-3)*2.3*(1+0.2)...
2023-03-23