age=eval(input("請輸入年齡:"))
if age > 18:
print('adult')
else:
print('teenager')
if age > 18:
print('adult')
else:
print('teenager')
2022-01-02
L = [[1,2,3],[5,3,2],[7,3,2]]
i = 0
j = 0
S = [0,0,0]
while i <= 2:
S[i]=2*(L[i][j]*L[i][j+1]+L[i][j]*L[i][j+2]+L[i][j+1]*L[i][j+2])
i = i + 1
print(S)
i = 0
j = 0
S = [0,0,0]
while i <= 2:
S[i]=2*(L[i][j]*L[i][j+1]+L[i][j]*L[i][j+2]+L[i][j+1]*L[i][j+2])
i = i + 1
print(S)
2021-12-18
L = [75, 92, 59, 68, 99]
sum = 0
for ch in L:
sum += ch
print(sum)
sum = 0
for ch in L:
sum += ch
print(sum)
2021-12-17
# coding: utf-8
score = 18
if score < 18:
if score >= 6:
print("青年")
else:
if score >= 3:
print("小孩子")
elif score == 18:
print("成年")
else:
print("大人")
score = 18
if score < 18:
if score >= 6:
print("青年")
else:
if score >= 3:
print("小孩子")
elif score == 18:
print("成年")
else:
print("大人")
2021-12-17
討論一下思路:
T = (1, 'CH', [3, 4])
tuple里面包含list,導致tuple是可變的,請修改T的定義,不改變基本數據類型的數據,使T是不可變的。
關于題干
目的:使其數據類型的數據不可變
拆分:那些數據是可變的?如何變成不可變的?
結果:列表中3,4是可變的,將其改為元組的形式即可
代碼實現:自己來吧。
T = (1, 'CH', [3, 4])
tuple里面包含list,導致tuple是可變的,請修改T的定義,不改變基本數據類型的數據,使T是不可變的。
關于題干
目的:使其數據類型的數據不可變
拆分:那些數據是可變的?如何變成不可變的?
結果:列表中3,4是可變的,將其改為元組的形式即可
代碼實現:自己來吧。
2021-12-15
T = ((1+2), ((1+2),), ('a'+'b'), (1, ), (1,2,3,4,5))
for i in T:
print(i)
3
for i in T:
print(i)
3
2021-12-15
sum = 1
num = 1
while num <=10:
sum=sum*num
num=num+1
print(sum)
num = 1
while num <=10:
sum=sum*num
num=num+1
print(sum)
2021-12-10
L = [75, 92, 59, 68, 99]
sum = 0.0
for a in L:
sum=sum+a
print(sum/len(L))
sum = 0.0
for a in L:
sum=sum+a
print(sum/len(L))
2021-12-10
x=(1,5,8,4)
def func(x):
if isinstance(x,list):
sum=0
for a in x:
sum=sum+a
return sum
if isinstance(x,tuple):
ji=1
for a in x:
ji=ji*a
return ji
print(func(x))
def func(x):
if isinstance(x,list):
sum=0
for a in x:
sum=sum+a
return sum
if isinstance(x,tuple):
ji=1
for a in x:
ji=ji*a
return ji
print(func(x))
2021-12-08
l=[1, 4, 5, 7, 9, 11]
def sub_sum(l):
suma=0
sumb=0
for a in l:
if a % 2 ==0:
suma=suma+a
else:
sumb=sumb+a
return suma,sumb
result=sub_sum(l)
print('偶數項和={}'.format(result[0]))
print('奇數項和={}'.format(result[1]))
def sub_sum(l):
suma=0
sumb=0
for a in l:
if a % 2 ==0:
suma=suma+a
else:
sumb=sumb+a
return suma,sumb
result=sub_sum(l)
print('偶數項和={}'.format(result[0]))
print('奇數項和={}'.format(result[1]))
2021-12-08
abc = 'Life is short,{}'
youneedPython = 'you need Python'
result = abc.format(youneedPython)
print(result)
youneedPython = 'you need Python'
result = abc.format(youneedPython)
print(result)
2021-12-08
x=[1,2,5,6,8]
def square_of_sum(x):
result=0
l=[]
for num in x:
result=num*num
l.append(result)
result=sum(l)
return result
m=square_of_sum(x)
print(m)
def square_of_sum(x):
result=0
l=[]
for num in x:
result=num*num
l.append(result)
result=sum(l)
return result
m=square_of_sum(x)
print(m)
2021-12-06