# coding: utf-8
s1 = '這是一句中英文混合的Python字符串:'
s2 = 'Hello World!'
print(s1+s2)
result = 's1{s2}'.format(s2='Hello World!')
print(result)
s1 = '這是一句中英文混合的Python字符串:'
s2 = 'Hello World!'
print(s1+s2)
result = 's1{s2}'.format(s2='Hello World!')
print(result)
2022-02-26
num = 0
sum = 0
while True:
if num>1000:
break
sum = sum + num
num = num + 2
print(sum)
sum = 0
while True:
if num>1000:
break
sum = sum + num
num = num + 2
print(sum)
2022-02-25
num = 1
plus = 1
while num <= 20:
plus = plus * num
num = num + 1
print(plus)
plus = 1
while num <= 20:
plus = plus * num
num = num + 1
print(plus)
2022-02-25
L = [75, 92, 59, 68, 99, 100, 87, 71]
sum = 0.0
count = len(L)
for score in L:
sum = sum + score
ave = sum/count
print(sum,count)
print(ave)
sum = 0.0
count = len(L)
for score in L:
sum = sum + score
ave = sum/count
print(sum,count)
print(ave)
2022-02-25
# Enter a code
age = 17
a = 'your age is {}, and you are a {}.'
if age>=18:
print(age, a.format(age, 'adult'))
else:
print(age, a.format(age, 'child'))
age = 17
a = 'your age is {}, and you are a {}.'
if age>=18:
print(age, a.format(age, 'adult'))
else:
print(age, a.format(age, 'child'))
2022-02-25
print(r'''\"To be, or not to be\": that is the question.
Whether it\'s nobler in the mind to suffer.''')
Whether it\'s nobler in the mind to suffer.''')
2022-02-23
因為短路計算,所以a=python時不計算or,直接返回python。
當b=空格,所以b=false;false or world=world
當b=空格,所以b=false;false or world=world
2022-02-20
def getSecond(elem):
return elem[1]
L = [('Alice',89), ('Bob',72), ('Candy',88), ('David',79), ('Ellena',99)]
#把list的每個元素的key賦值為各個元素的下標為1的值,然后list按key的數值大小進行排序
L.sort(key=getSecond,reverse=True)
print(L)
list = []
for item in L:
list.append(item[0])
print(list)
return elem[1]
L = [('Alice',89), ('Bob',72), ('Candy',88), ('David',79), ('Ellena',99)]
#把list的每個元素的key賦值為各個元素的下標為1的值,然后list按key的數值大小進行排序
L.sort(key=getSecond,reverse=True)
print(L)
list = []
for item in L:
list.append(item[0])
print(list)
2022-02-20
L = ['Alice', 'Bob', 'Candy', 'David', 'Ellena']
a=L.pop(2)
s=L.pop(2)
print(a,s)
a=L.pop(2)
s=L.pop(2)
print(a,s)
2022-02-19