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  • 列表字典組合

    # coding=utf-8

    stus = []

    stu1 = {"no":"111","name":"張三","age":23,"nation":"漢","birthday":"1998-01-01","father":{"name":"張建國","company":"中國移動","job":"客戶經理"},"mother":{"name":"吳燕玲","company":"師大附中","job":"語文老師"}}

    stus.append(stu1)

    print(stus)

    name = stus[-1]["name"]

    print(name)


    stu2 = {"no":"112","name":"李四","age":23,"nation":"漢","birthday":"1998-01-01","father":{"name":"李建國","company":"中國聯通","job":"客戶經理"},"mother":{"name":"張麗麗","company":"人民醫院","job":"外科醫生"}}

    stus.append(stu2)

    print(stus)


    name = stus[-1]["name"]

    print(name)

    fatherName = stus[-1]["father"]["name"]

    print(fatherName)

    http://img1.sycdn.imooc.com//6095464100019eea19080167.jpg

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  • 列表字典組合

    # coding=utf-8

    stus = []

    stu1 = {"no":"111","name":"張三","age":23,"nation":"漢","birthday":"1998-01-01","father":{"name":"張建國","company":"中國移動","job":"客戶經理"},"mother":{"name":"吳燕玲","company":"師大附中","job":"語文老師"}}

    stus.append(stu1)

    print(stus)

    name = stus[-1]["name"]

    print(name)


    stu2 = {"no":"112","name":"李四","age":23,"nation":"漢","birthday":"1998-01-01","father":{"name":"李建國","company":"中國聯通","job":"客戶經理"},"mother":{"name":"張麗麗","company":"人民醫院","job":"外科醫生"}}

    stus.append(stu2)

    print(stus)


    name = stus[-1]["name"]

    print(name)

    fatherName = stus[-1]["father"]["name"]

    print(fatherName)

    http://img1.sycdn.imooc.com//6095464100019eea19080167.jpg

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  • 列表字典組合

    # coding=utf-8

    stus = []

    stu1 = {"no":"111","name":"張三","age":23,"nation":"漢","birthday":"1998-01-01","father":{"name":"張建國","company":"中國移動","job":"客戶經理"},"mother":{"name":"吳燕玲","company":"師大附中","job":"語文老師"}}

    stus.append(stu1)

    print(stus)

    name = stus[-1]["name"]

    print(name)


    stu2 = {"no":"112","name":"李四","age":23,"nation":"漢","birthday":"1998-01-01","father":{"name":"李建國","company":"中國聯通","job":"客戶經理"},"mother":{"name":"張麗麗","company":"人民醫院","job":"外科醫生"}}

    stus.append(stu2)

    print(stus)


    name = stus[-1]["name"]

    print(name)

    fatherName = stus[-1]["father"]["name"]

    print(fatherName)

    http://img1.sycdn.imooc.com//6095464100019eea19080167.jpg

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  • #鍵值對存儲key不能重復,value可以重復

    # coding=utf-8

    lisa = {"name":"Lisa","age":23}

    print(lisa)

    print(lisa["age"])

    lisa["age"] = 26

    lisa["height"] = 166

    print(lisa)

    lisa.pop("age")

    print(lisa)

    http://img1.sycdn.imooc.com//60953fe9000134f203950149.jpg

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  • 左閉右開[0:2]取第一個和第二個

    反向索引最后一個下標是-1

    # coding=utf-8

    books = ["紅樓夢","三國演義","水滸傳","西游記","聊齋志異"]

    print(books[0:4])

    print(books[0:-1])

    http://img1.sycdn.imooc.com//6065e81700013a5a05740160.jpg

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  • # coding=utf-8

    books = ["紅樓夢","三國演義","水滸傳","西游記","聊齋志異"]

    print(books[0])

    http://img1.sycdn.imooc.com//6065e6ba00013c5004110107.jpg

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  • int取整

    %取余

    # coding=utf-8

    n=154

    a=int(n/100)

    b=int(n%100/10)

    c=n%10

    print(a)

    print(b)

    print(c)

    re=a*a*a+b*b*b+c*c*c

    if n==re:

    print(n,end="")

    print("是水仙花數")

    else:

    print(n,end="")

    print("不是水仙花數")


    154除以100取余54,54除以10等于5.4取整為5

    http://img1.sycdn.imooc.com//6065e3fe0001a39705290138.jpg

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  • # coding=utf-8

    score = 30

    if score >=60:

    print("考試通過!")

    if score >= 90:

    print("名列前茅,重點表揚")

    else:

    print("繼續努力,潛力巨大")

    else:

    print("考試未通過,還需努力")

    http://img1.sycdn.imooc.com//6065e07a00019ec003260095.jpg


    注意縮進

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    0 采集 收起 來源:嵌套分支

    2021-04-01

  • 整型(整數)不需要加雙引號,加了雙引號就是字符串

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  • 雙引號一定標識字符串

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  • # coding=utf-8

    la = "德語"

    if la == "德語" :

    print("Ich liebe dich")

    elif la == "韓語" :

    print("???")

    elif la == "英語" :

    print("I love you")


    else :

    print("我愛你")

    http://img1.sycdn.imooc.com//604a30900001eab202770092.jpg


    由于是用記事本打開編輯的所以對編碼有要求最終保存為utf-8 文件開頭對應utf-8? ?猜測是這個原因,也許我用個正經編輯器就不會這樣

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    0 采集 收起 來源:多分支判斷

    2021-03-11

  • 注意 () not and or的優先級


    # coding=gbk

    r1 = 1 != 1 or 8 < 2 and 6? > 3

    print(r1)

    r2 = 1 != 1 or not 8 < 1 and 6 > 3

    print(r2)

    r3 = 1 != 1 or not (8 < 1 and 6 > 3)

    print(r3)


    x = 700

    re = (1000 - x) * 30

    print(re)

    if(re >= 1 and re <= 10000) :

    print("結果落在區間內")

    else :

    print("結果未落在區間內")

    http://img1.sycdn.imooc.com//604a2a3600019e9404570151.jpg

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    0 采集 收起 來源:邏輯運算符

    2021-03-11

  • # coding=gbk

    x=1600

    re = (1000-x)*30

    print(re)

    if re >10000 :

    print("結果大于10000")

    else :

    print("結果小于10000")

    http://img1.sycdn.imooc.com//604a263d0001906b03120120.jpg

    True False? 首字母是大寫的

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  • # coding=gbk

    if 8 > 6 :

    print("判斷條件成立")

    else :

    print("判斷條件不成立")

    http://img1.sycdn.imooc.com//604a249300015d3e04120108.jpg

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    0 采集 收起 來源:分支判斷

    2021-03-11

  • yntaxError: Non-ASCII character '\xe5' in file index.py on line 7, but no encoding declared; see http://python.org/dev/p


    開頭加# -*- coding: UTF-8 -*-

    不好使就加#coding=gbk? 總有一款適合你

    http://img1.sycdn.imooc.com//604a233b0001c5e203010216.jpg

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