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矩陣是我們常用的數學工具，請你編寫一個矩陣的工具類，要求包含矩陣的乘法功能，當然，拷貝也是必要的
class Mat
{
public:
int row = 0;
int col = 0;
float * * mat = nullptr;
private:
void init(int row, int col)
{
if (row && col) {
mat = new float*[row];
for (int i = 0; i < row; i++) {
mat[i] = new float[col];
for (int j = 0; j < col; j++){
mat[i][j] = 0;
if(i == j){
mat[i][j] = 1;
}
}
}
}
}
public:
Mat(int row = 0, int col = 0)
{
this->row = row;
this->col = col;
init(row, col);
}
Mat(const Mat &m)
{
this->row = m.row;
this->col = m.col;
init(row, col);
for (int i = 0; i < row; i++){
for (int j = 0; j < col; j++){
mat[i][j] = m.mat[i][j];
}
}
}
~Mat()
{
if (mat != nullptr) {
for (int i = 0; i < row; i++){
if (mat[i]) {
delete[] mat[i];
mat[i] = nullptr;
}
}
if (mat){
delete[] mat;
}
mat = nullptr;
}
}
Mat & operator = (const Mat &m)
{
if (mat != nullptr) {
for (int i = 0; i < row; i++){
if (mat[i]) {
delete[] mat[i];
mat[i] = nullptr;
}
}
if (mat){
delete[] mat;
}
mat = nullptr;
}
row = m.row;
col = m.col;
init(row, col);
for (int i = 0; i < row; i++){
for (int j = 0; j < col; j++){
mat[i][j] = m.mat[i][j];
}
}
return *this;
}
Mat operator * (const Mat &m)
{
EyerMat res(row, m.col);
for (int i = 0; i < res.row; i++) {
for (int j = 0; j < res.col; j++) {
res.mat[i][j] = 0.0f;
}
}
if (m.row != col){
}
else {
for (int i = 0; i < res.row; i++) {
for (int j = 0; j < res.col; j++) {
for (int k = 0; k < res.row; k++) {
res.mat[i][j] += mat[i][k] * m.mat[k][j];
}
}
}
}
return res;
}
}
請驗證，完成請求
由于請求次數過多，請先驗證，完成再次請求
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